Quantitative
Aptitude Number Series Practice Questions – Set 14
Directions (1 – 2): Find the wrong term in the
following number series?
1. 10, 14, 28, 32, 64, 68, 132
a) 28
b) 32
c) 64
d) 132
2. 10
15
24
35 54
75 100
a) 75
b) 35
c) 24
d) 15
e) 54
Directions (3 – 15): What should come in place of
question mark (?) in the following question?
3. 3
7
14
23
? 49
a) 47
b) 36
c) 24
d) 41
e) 44
4. 123, 126, 124, 127, ?, 128, 126, 129
a) 127
b) 125
c) 126
d) 128
e) None of these
5. 41, 328, 5248, ?, 10747904
a) 102444
b) 5431552
c) 167936
d) 127688
e) None of these
6. 226, 222, 206, 170, 106, ?
a) 84
b) 100
c) 78
d) 6
e) 36
7. 117
389
525
593
627 (?)
a) 624
b) 644
c) 634
d) 654
e) 664
8. 3, 23, 43, ?, 83, 103
a) 33
b) 53
c) 63
d) 73
e) None of these
9. 4, 19, 49, 94, 154, ?
a) 223
b) 225
c) 229
d) 239
e) None of these
10. 10
17
48 165
688 3475 ?
a) 19892
b) 19982
c) 21892
d) 20892
e) None of these
11. 7
8
16
43 107
(?)
a) 186
b) 196
c) 194
d) 232
e) None of these
12. 4 13 17 ? 30 39
a) 29
b) 21
c) 26
d) 19
e) None of these
13. 0, 2, 6, 12, 20, 30, 42, ?
a) 56
b) 62
c) 49
d) 55
e) 58
14. 11, 12, 26, 81, ?
a) 324
b) 328
c) 320
d) 280
e) None of these
15. 5, 11, 23, 47, ?
a) 95
b) 93
c) 96
d) 97
e) None of these
Solutions:
1. D) The pattern of the given number
series is as:
→10,
→10 + 4 = 14,
→14 × 2 = 28,
→28 + 4 = 32,
→ 32 × 2 = 64,
→ 64 + 4 = 68
→ 68 × 2 = 136,
(instead of 132)
Hence, the wrong term of
the given number series is 132. The correct term is 136.
2. B) 10
+ 5 = 15 (By adding 5)
15 + 9 = 24 (By adding 5
+ 4 =9)
24 + 13 = 37(By adding 9
+ 4 =13)
37 + 17 = 54 (By adding
13 + 4 =17)
54 + 21 = 75 (By adding
17 + 4 =21)
75 + 25 = 100 (By adding
21 + 4 =25)
Hence, the wrong number =
35
3. B) The
pattern of given series is as –
⇒ 12 + 2 = 3
⇒ 22 + 3 = 7
⇒ 32 + 5 = 14
⇒ 42 + 7 = 23
⇒ 52 + 11 = 36
⇒ 62 + 13 = 49
Hence required term is
36.
4. B) We
observe that
123 + 3 = 126 and 126 – 2
= 124
124 + 3 = 127
128 – 2 = 126 and 126 + 3
= 129
So, the series is a
pattern of +3, -2, +3, -2
Hence, the next term in
the series is: 127 – 2 = 125
5. C) 41×
8 = 328
328 × 16 = 5248
5248 × 32 = 167936
167936 × 64 = 10747904
So, the missing number
is: 167936
6. D) The
pattern of the given number series is:
⇒ 226 – 22 =
222
⇒ 222 – 42 =
206
⇒ 206 – 62 =
170
⇒ 170 – 82 =
106
⇒ 106 – 102 =
6
7. B) The
pattern of given series is –
389 – 117 = 272
525 – 389 =136
593 – 525 = 68
627 – 593 = 34
? – 627 = 17
⇒ ? = 627 + 17 = 644
8. C) Let
the missing number be x, then
23 – 3 = 20
43 – 23 = 20
X – 43 = 20 ⇒ x = 63
83 – 63 = 20
103 – 83 = 20
9. C) 4
+ 15 = 19
19 + 30 = 49
49 + 45 = 94
94 + 60 = 154
154 + 75 = 229
10. D) 17
= 10 × 1 + 7 × 1
48 = 17 × 2 + 7 × 2
165 = 48 × 3 + 7 × 3
688 = 165 × 4 + 7 × 4
3475 = 688 × 5 + 7 × 5
20892 = 3475 × 6 + 7 × 6
11. D) The
pattern may be evaluated as:
→ 7
→ 7 + 13 =
8
→ 8 + 23 =
16
→ 16 + 33 =
43
→ 43 + 43 =
107
Hence next number must
be,
→ 107 + 53 =
232
∴The required term in the given number series is 232.
12. C) The
pattern can be analyzed as:
→ 13 – 4 = 9 = 32
→ 17 – 13 = 4 = 22
Similar pattern is
followed from the end side i.e.
→ 39 – 30 = 9 = 32
Hence next number must
be:
→ 30 – 22 =
26
∴ The required term in the given number series is 26.
13. A) Difference
between two numbers is in multiplication of 2.
2 – 0 = 2
6 – 2 = 4
12 – 6 = 6
20 – 12 = 8
30 – 20 = 10
42 – 30 = 12
So the next difference
should be 14
⇒Next number = 42 + 14 = 56
14. B) The
pattern of given series is as follows:
→ 11
→ 11 × 1 + 1 = 12
→ 12 × 2 + 2 = 26
→ 26 × 3 + 3 = 81
The next number
→ 81 × 4 + 4 = 328
Hence the required term
of given sequence is 328.
15. A) The
pattern of given sequence can be evaluated as:
→ 5
→ 5 × 2 + 1 = 11
→ 11 × 2 + 1 = 23
→ 23 × 2 + 1 = 47
Hence, the next number
must be
→ 47 × 2 + 1 = 95
Hence the required term
of given number is 95.
