Coding and
Decoding Practice Questions – Set 14
Directions (1 – 5): Read the following information
carefully and answer the questions given beside:
In a certain code
language
‘729 961 246 361’ is written as ‘422 853
275 253’
‘289 784 576’ is written as ‘112 341
716’
‘625 841 324’ is written as ‘734
134 121’
1. ‘532’ is the code for which of the following?
a) 51
b) 942
c) 641
d) 486
e) Can’t be determined
2. What is the code for the number ‘786’?
a) 81
b) 169
c) 121
d) 144
e) None of these
3. What is the code for the number ‘942’?
a) 532
b) 224
c) 314
d) 725
e) None of these
4. What is the code for the number ‘246’?
a) 422
b) 253
c) 853
d) 275
e) None of these
5. What is the code for the number ‘521 134 289 ’?
a) 314 312 761
b) 413 312 716
c) 123 314 167
d) 413 321 761
e) None of these
Directions
(6 – 10): In each question below is given a group of
numbers / symbols followed by five combinations of letter codes numbered (1),
(2), (3), (4) and (5). You have to find out which of the combinations correctly
represents the group of numbers / symbols based on the following coding system
and the conditions and mark the number of that combination as your answer:
Conditions:
1)
If the second element is an even number and the last element is a symbol then
that even number is to be coded as the code for the symbol.
2) If
both the second and third elements are symbols, the codes for these
symbols are to be interchanged.
3) If
there are no even numbers then the codes of the first and the third elements
have to be interchanged.
6. 5 & @ 2 ¥ 6 * 1 β ©
a) QJAYBCZSHE
b) QAJCBYSZHE
c) QJAYCSBZHE
d) QAJCSYBZHE
e) QJACBYSZHE
7. ¥ 8 $ 57 ! 4 * µ #
a) BKUQDMFSWR
b) RKUQDMFSWB
c) BRUQDMFSWR
d) BRUDQMFSWR
e) BKUQDMFSWB
8. 1 @ 7 ! $ ®3 * α &
a) DADMUGNSVJ
b) ZJDMUGNSVA
c) MAZDUGNSVJ
d) DJZMUGNSVA
e) MJZNUGDSVA
9. 2 ¥ # 7 @ 59 ! * ∩
a) CRBJDQOMSP
b) CRBDJQOMSP
c) RNCDJQMOSP
d) CBRDJQOMSP
e) CBRQJDOMSP
10. ! 62 $ 3 # & 8 * ¥
a) MBCUNRAKSB
b) MNCUYKARSB
c) MYCUNRAKSB
d) MNCUYRAKSB
e) MBCUNKARSB
Directions
(11 – 15): Study the information below and answer the following question:
In a certain code
language,
‘Arrive today eagles later’ is written as 21*R, 6$A, 14$O, 25*A
‘Begin work faster table’ is written as 14$A,
17%O, 26*A, 22$E
‘Length error arrow burn’ is written as 6*E,
25$R, 22%U, 21$R
‘Trial better than wisdom’ is written as 14$R,
14%H, 22*E, 17*I
11. The
code for the word ‘table’
a) 26*A
b) 17%O
c) 14$A
d) 22$ E
e) None of these
12. The
code word 6$A for the word
a) Later
b) Arrive
c) Earlier
d) Today
e) Either 1 or 3
13. Find
the code word for the word ‘Burn’?
a) 25$R
b) 22%U
c) 21$R
d) 6*E
e) Can’t be determined
14.
According to the given code, what is the code for ‘M’?
a) 12
b) 8
c) 10
d) 7
e) Can’t be determined
15. By
using the given code word, find the code word for ‘Better Luck Next Arrive’ ?
a) 22$E, 21$R, 6*U, 8%E
b) 8*E, 21*R, 22%E, 6%U
c) 22*E, 6%U, 8%E, 21*R
d) 21%R, 22$E, 6*U, 8%E
e) 6$U, 22*E, 8*E, 21%R
Solution:
(1 – 5): Explanation:
In this question the
first digit of every given number is coded as the difference of first digit and
the second digit of the given number.
For instance, in 729 the
first and the second digit are 7 and 2 respectively and the difference between
them is 7 -2 = 5.
Next, the second digit
of the given number is coded as the difference of the second digit and the
third digit of the given number.
In 729 the second digit
and the third digit are 2 and 9 respectively and the difference between them is
9 - 2 = 7.
Similarly, the third
digit of the given number is coded as the difference of the third digit and the
first digit of the given number.
In 729 the third digit
and the first digit are 9 and 7 respectively and the difference between them is
9 - 7 = 2
Clearly, the code for 729
will be 572.
In the final step the
obtained codified digits are arranged in a reverse order.
In case of 729, the
obtained digits are 5, 7 and 2 respectively. Therefore, the final code for 729
will be 275.
1. C) 2. C) 3. D) 4. A) 5. B)
6. E) Here, 2nd rule
implies i.e., both the second and third elements are symbols.
Therefore, 5 & @ 2 ¥
6 * 1 β © is coded as QJACBYSZHE.
7. C) Here,
1st rule implies i.e., second element is an even number and the
last element is a symbol.
Therefore, ¥ 8 $ 57 ! 4 *
µ # is coded as BRUQDMFSWR.
8. D) Here
3rd rule implies i.e., there are no even numbers.
Therefore, 1 @ 7 ! $ ®3 *
α & is coded as DJZMUGNSVA.
9. B) Here,
2nd rule implies i.e., second and third elements are symbols.
Therefore, 2 ¥ # 7 @ 59 !
* ∩ is coded as CRBDJQOMSP.
10. A) Here,
1st rule implies i.e., second element is an even number and the
last element is a symbol.
Therefore, ! 62 $ 3 #
& 8 * ¥ is coded as MBCUNRAKSB.
(11 – 15):
The logic for all the
above code is:
Number that denotes 1st letter
of the word: A-21, B-22, C-23, …, G-1,……, Z -20
Then the symbol is
denoted with respect to no. of letters,
$ => 5 letter
word; % => 4 letter word; * => 6 letter word
Next, second letter of
the word will come.
11. C) 12. A) 13. B)
14. D) 15. C)
