Percentages Practice Questions – Set 2
1. The difference between 20% of a number and 4/5th of the same number
is 2499. What is 2/7th of that number ?
a) 2156
b) 1190
c) 1090
d) 1465
Answer:
B)
Explanation:
Let the number be x
[20% = 20 / 100 = 1/5 which is less than 4/5]
(4x / 5) – (x / 5) = 2499à 3x / 5 = 2499
x = (2499 × 5) / 3 = 4165
4165 × (2/7) = 1190
2. If the numerator of a fraction is increased by 300% and the
denominator is increased by 200%, the resultant fraction is 4/15. What is the
original fraction ?
a) 3/5
b) 4/5
c) 2/5
d) 1/5
e) None of these
Answer:
D)
Explanation:
Let the original fraction be x / y. so, (x + 300% x)
/ (y + 200% y) = 4/15
(x × 400) / (y × 300) = 4/15
x/y =( 4/15) × (3/4)= 1/5
3. Kajal spends 55% of her monthly income on grocery, clothes and
education in the ratio of 4 : 2 : 5 respectively. If the amount spent on
clothes is Rs. 5,540. What is Kajal’s monthly income ?
a) Rs. 55,400
b) Rs. 54,500
c) Rs. 55,450
d) Rs. 55,650
e) None of these
Answer:
A)
Explanation:
If the monthly income of Kajal be Rs. x, then
x × (55 / 100) × [2 / (4 + 2 + 5)] = 5540
x × (55 / 100) × (2/11) = 5540à x = (5540 × 100 ×
11) / (55 × 2)
x = Rs. 55400
4. 35 percent of a number is two times 75 percent of another number.
What is the ratio between the first and the second numbers respectively ?
a) 35 : 6
b) 31 : 1
c) 23 : 7
d) 32 : 9
e) None of these
Answer:
E)
Explanation:
x × (35 / 100) = y × (75 / 100) × 2
x × 35 = y × 2 × 75à x × 7 = 30y
x/y = 30/7
5. Last year there were 610 boys in a school. The number decreased by 20
percent this year. How many girls are there in the school if the number of
girls is 175 percent of the total number of boys in the school this year ?
a) 854
b) 848
c) 798
d) 782
e) None of these
Answer:
A)
Explanation:
Present population of boys = (610 × 80) / 100 = 488
Number of girls = (488 × 175) / 100 = 854
6. The salary of Anup is 30% more than that of Barun. Find by what
percentage is the salary of Barun less than that of Anup ?
a) 26.12%
b) 21.23%
c) 23.07%
d) 27.03%
e) None of these
Answer:
C)
Explanation:
Required percentage = 30 / (100 + 30) × 100
300 / 13 = 23.07%
7. Akash scored 73 marks in subject A. He scored 56% marks in subject B
and x marks in subject C. Maximum marks in each subject were 150. The overall
percentage marks obtained by Akash in all the three subjects together were 54%.
How many marks did he score in subject C?
a) 84
b) 86
c) 79
d) 73
e) None of these
Answer:
B)
Explanation:
Marks obtained by Akash in subject B = (150 × 56) /
100 = 84
Total marks obtained by Akash = (450 × 54) / 100 =
243
Therefore, Marks obtained in subject C = 243 – 73 –
84 = 86
8. What value will you obtain if twenty five percent of 2340 is
subtracted from four-ninth of square of 36 ?
a) 9
b) -18
c) 18
d) -9
e) 3
Answer:
D)
Explanation:
Required answer = (4/9) × (36)2 –
2340 × (25 / 100)
= 576 – 585 = -9
9. In a class of 35 students and 6 teachers, each student got sweets
that are 20% of the total number of students and each teacher got sweets that
are 40% of the total number of students. How many sweets were there?
a) 245
b) 161
c) 406
d) 84
e) None of these
Answer:
E)
Explanation:
Number of sweets got by each student = (35 × 20) /
100 = 7
Number of sweets got by each teacher = (35 × 40) /
100 = 14
Total number of sweets = 35 × 7 + 6 × 14 = 245 + 84
= 329
10. Prithvi spent Rs. 89,745 on his college fees, Rs. 51,291 on
Personality Development Classes and the remaining 27% of the total amount he
had as cash with him. What was the total amount ?
a) Rs. 1,85,400
b) Rs. 1,89,600
c) Rs. 1,91,800
d) Rs. 1,93,200
e) None of these
Answer:
D)
Explanation:
Let the total amount with Prithvi be Rs. x.
percentage of amount spent = (100 – 27) = 73%
According to the question.
73% of x = (89745 + 51291) => (x × 73) / 100 =
141036
=> X = (141036 × 100) / 73 = Rs. 193200
