Reasoning Practice Questions for SBI PO 2017

Mentor for Bank Exams
Reasoning Practice Questions for SBI PO 2017
Directions (1 – 5): In these questions, relationship between different elements is shown in the statements. These statements are followed by two conclusions.
Give Answer
a) If only Conclusion I is true
b) If only Conclusion II is true
c) If either Conclusion I or II is true
d) If neither Conclusion I nor II is true
e) If both conclusions I and II is true
1. Statements:  H ≥ I = J > K ≤ L
Conclusions:
I.   K < H
II.  L ≥ I
2. Statements: S > C ≥ O, P < C
Conclusions:
I.  O < P
II. S > P
3. Statements: A = B ≤ C, A > R
Conclusions:
I.  B > R
II. R < C
4. Statements: D > E ≤  F, J < F
Conclusions:
I.  D > J
II. E < J
5. Statements: P < Q > T, R ≥ Q
Conclusions:
I.  R > P
II. T < R
Directions (6 – 10): Answer the questions on the basis of the information given below.
A number arrangement machine when given an input of numbers/words, rearranges them following a particular rule in each step. The following is an illustration of input and steps of rearrangement.
Input: dump 7 sat tin 8 5 born 9 pet 4
Step 1: set dump 7 tin 8 5 born 9 pet 4
Step 2: set dump 7 tin 8 5 born 9 pet  61
Step 3: set pit dump 7 tin 8 5 born 9 61
Step 4: set pit dump 7 tin 8 born 9 61 52
Step 5: set pit ton dump 7 8 born 9 61 52
Step 6: set pit ton dump 8 born 9 61 52 94
Step 7: set pit ton burn dump 8 9 61 52 94
Step 8: set pit ton burn dump 9 61 52 94 46
Step 9: set pit ton burn damp 9 61 52 94 46
Step 10: set pit ton burn damp 61 52 94 46 18
This is the final arrangement and step 10 is the last step for this input.
Input: 11 pill but 9 5 ten 8 bat 7 doll
6. Which word/number is third to right of seventh element from right end in step 6?
a) 94
b) bet
c) tin
d) 11
e) doll
7. In step 4, if ‘tin’ interchanges position with ‘but’ and ‘11’ with ‘52’, then how many words are there in between ‘tin’ and ‘52’?
a) none
b) one
c) two
d) three
e) more than three
8. How many numbers/words are between ‘tin’ and ‘but’ in step 7?
a) none
b) one
c) two
d) three
e) more than three
9. What is the sum of the numbers which are fourth from left end and second from right end in step 5?
a) 36
b) 47
c) 63
d) 49
e) 45
10. What is the sum of digits of the sum of the numbers which are fourth from right end in step 9 and second from right end in step 6?
a) 20
b) 9
c) 19    
d) 11
e) 15
Solutions:
1. A) Conclusions
I. K < H  is True
II. L ≥ I  is False
Only Conclusion I is True hence answer is Option A.
2. B) Conclusions
I. O < P  is False
II. S > P  is True
Only Conclusion II is True hence answer is Option B.
3. E) Given that, A = B ≤ C
and             A > R
On combining the statement we will get : R < A = B ≤  C
Conclusions
I. B > R  is True
II. R < C  is True
Both the conclusions are True hence answer is Option E
4. D) Given that, D > E ≤ F
and             J < F
On combining the statement we will get : D > E ≤ F  > J
Conclusions
I. D > J  is False
II. E < J  is False
Both Conclusions are False  hence answer is Option D
5. E) Given that, P < Q > T
and             R ≥  Q
On combining the statement we will get :
P < Q ≤ R and R ≥ Q > T
Conclusions
I. R > P  is True
II. T < R  is True
Both Conclusions are True   hence answer is Option E
(6 – 10):
If we see the last step, it is found that changes are done in vowels as – a->e, e->I, i->o, o->u and u->a. And also words in each step are taken according to the sequence of vowels which is a, e, I, o, u
And for numbers: Number are taking in ascending order, squared and digits reversed, so 4 => 4^2 = 16, become 61
Input: 11 pill but 9 5 ten 8 bat 7 doll
Step 1: bet 11 pill but 9 5 ten 8 7 doll
Step 2: bet 11 pill but 9 ten 8 7 doll 52
Step 3: bet tin 11 pill but 9 8 7 doll 52
Step 4: bet tin 11 pill but 9 8 doll 52 94
Step 5: bet tin poll 11 but 9 8 doll 52 94
Step 6: bet tin poll 11 but 9 doll 52 94 46
Step 7: bet tin poll dull 11 but 9 52 94 46
Step 8: bet tin poll dull 11 but 52 94 46 18
Step 9: bet tin poll dull bat 11 52 94 46 18
Step 10: bet tin poll dull bat 52 94 46 18 121 
6. E)   7. B)   8. D)
9. C) 11 + 52 = 63
10. D) 52 + 94 = 146, so sum of digits of 146 is 1 + 4 + 6 = 11